The /3 subnet

A /3 subnet uses the mask 224.0.0.0 and holds 536,870,912 addresses, 536,870,910 of them usable.

/3
Prefix length
224.0.0.0
Subnet mask
31.255.255.255
Wildcard mask
536,870,910
Usable hosts

A /3 is a very large IPv4 block. Its mask is 224.0.0.0 and it holds 536,870,912 addresses, which puts it at the scale of a regional allocation or an entire private supernet rather than a single LAN.

Networks this size are almost always carved into smaller subnets before use. You will see a /3 as an aggregate route or a private-address supernet such as 10.0.0.0/8, not as a single broadcast domain.

Below you can see the exact network, broadcast, and host range for any /3 you enter, calculated instantly in your browser.

Calculate a /3 network

Accepts CIDR (192.0.2.0/24), IP + mask (192.0.2.0 255.255.255.0), or a bare IP (defaults to /24).

Network address0.0.0.0
Usable host range0.0.0.1 - 31.255.255.254
Broadcast address31.255.255.255
Usable hosts536,870,910
Subnet mask224.0.0.0
Wildcard mask31.255.255.255
CIDR notation0.0.0.0/3
Total addresses536,870,912
IP (binary)00001010.00000000.00000000.00000000
Mask (binary)11100000.00000000.00000000.00000000
Try:

Example: 10.0.0.0/3

Taking 10.0.0.0/3 as a worked example, the block breaks down like this:

Network address0.0.0.0
Usable range0.0.0.1 - 31.255.255.254
Broadcast address31.255.255.255
Total addresses536,870,912
Usable hosts536,870,910
Size32 class A blocks

Frequently asked questions

What is the subnet mask for a /3?

A /3 uses the subnet mask 224.0.0.0. Its wildcard mask, used in access lists, is 31.255.255.255.

How many hosts are in a /3 subnet?

A /3 has 536,870,912 total addresses and 536,870,910 usable hosts (the total minus the network and broadcast addresses, except for /31 and /32).

What is a /3 used for?

Very large network. It is equivalent to 32 class A blocks.

How do I calculate a /3 network?

Set the host bits to zero for the network address and to one for the broadcast address. The calculator on this page does it for any /3 block you enter.