The /4 subnet

A /4 subnet uses the mask 240.0.0.0 and holds 268,435,456 addresses, 268,435,454 of them usable.

/4
Prefix length
240.0.0.0
Subnet mask
15.255.255.255
Wildcard mask
268,435,454
Usable hosts

A /4 is a very large IPv4 block. Its mask is 240.0.0.0 and it holds 268,435,456 addresses, which puts it at the scale of a regional allocation or an entire private supernet rather than a single LAN.

Networks this size are almost always carved into smaller subnets before use. You will see a /4 as an aggregate route or a private-address supernet such as 10.0.0.0/8, not as a single broadcast domain.

Below you can see the exact network, broadcast, and host range for any /4 you enter, calculated instantly in your browser.

Calculate a /4 network

Accepts CIDR (192.0.2.0/24), IP + mask (192.0.2.0 255.255.255.0), or a bare IP (defaults to /24).

Network address0.0.0.0
Usable host range0.0.0.1 - 15.255.255.254
Broadcast address15.255.255.255
Usable hosts268,435,454
Subnet mask240.0.0.0
Wildcard mask15.255.255.255
CIDR notation0.0.0.0/4
Total addresses268,435,456
IP (binary)00001010.00000000.00000000.00000000
Mask (binary)11110000.00000000.00000000.00000000
Try:

Example: 10.0.0.0/4

Taking 10.0.0.0/4 as a worked example, the block breaks down like this:

Network address0.0.0.0
Usable range0.0.0.1 - 15.255.255.254
Broadcast address15.255.255.255
Total addresses268,435,456
Usable hosts268,435,454
Size16 class A blocks

Frequently asked questions

What is the subnet mask for a /4?

A /4 uses the subnet mask 240.0.0.0. Its wildcard mask, used in access lists, is 15.255.255.255.

How many hosts are in a /4 subnet?

A /4 has 268,435,456 total addresses and 268,435,454 usable hosts (the total minus the network and broadcast addresses, except for /31 and /32).

What is a /4 used for?

Very large network. It is equivalent to 16 class A blocks.

How do I calculate a /4 network?

Set the host bits to zero for the network address and to one for the broadcast address. The calculator on this page does it for any /4 block you enter.