Subnet for 50 hosts
A network that needs 50 hosts fits in a /26, mask 255.255.255.192, with 62 usable addresses.
A network built for 50 hosts needs a /26. The mask is 255.255.255.192, and its 62 usable addresses leave 12 spare for growth.
The next smaller block, a /27, only allows 30 usable addresses, which is not enough for 50 hosts. That makes /26 the smallest block that fits.
Enter any address below to see the exact network, broadcast, and host range for a /26 block.
Calculate a /26 network
Accepts CIDR (192.0.2.0/24), IP + mask (192.0.2.0 255.255.255.0), or a bare IP (defaults to /24).
11000000.00000000.00000010.0000000011111111.11111111.11111111.11000000Example: 192.0.2.0/26
Taking 192.0.2.0/26 as a worked example, a /26 block breaks down like this:
| Network address | 192.0.2.0 |
|---|---|
| Usable range | 192.0.2.1 - 192.0.2.62 |
| Broadcast address | 192.0.2.63 |
| Total addresses | 64 |
| Usable hosts | 62 |
Frequently asked questions
What subnet mask do I need for 50 hosts?
A network with 50 hosts fits in a /26, which uses the mask 255.255.255.192 and provides 62 usable addresses.
How many addresses does a /26 block have in total?
A /26 has 64 total addresses, 62 of them usable (the total minus the network and broadcast addresses, except for /31 and /32).
Does a /26 waste any addresses for 50 hosts?
Yes, 12 addresses of headroom. A /26 provides 62 usable addresses for the 50 you need, and the next smaller block, a /27, does not hold enough.
How do I work this out myself?
Find the smallest power of two, minus two, that is at least 50. That takes 6 host bits, which leaves a /26 prefix. See how to calculate a subnet mask for the full method.